Question

Ache o vértice da função: y = 2x² - 4x + 5

Answer 1

$2x^2-4x+5\\\Delta=(-4)^2-4.2.5\\\Delta=16-40\\\Delta=-24$

$\boxed{Xv= \frac{-b}{2a}~\to~Xv= \frac{4}{4}~\to~Xv= 1}$

$\boxed{Yv= \frac{-\Delta}{4a} ~\to~Yv= \frac{24}{8} ~\to~Yv=3}$


$V(1~:~3)$

 Ou deriva e iguala a zero

$y=2x^2-4x+5\\y'=4x-4$

$4x-4=0\\4x=4\\ \\x=1$

$y=2(1)^2-4.1+5\\y=2-4+5\\y=3$