Question

-3x²+6x=0 me ajudem pfvv!!

Answer 1

$- 3 {x}^{2} + 6x = 6 \\ Δ = {6}^{2} - 4 \times - 3 \times 0 \\ Δ = 36 + 0 \\ Δ = 36$

$x = \frac{ - 6 + - \sqrt{36} }{2 \times - 3} = \frac{ - 6 + - 6}{ - 6}$

$x' = \frac{ - 6 + 6}{ - 6} = 0 \\ x'' = \frac{ - 6 - 6}{ - 6} = \frac{ - 12}{ - 6} = + 2$