Question

x²-3x+4=-7x+10
Me ajudem pessoal

Answer 1

Resposta:

$x^2-3x+4=-7x+10\\ \\ x^2-3x+7x+4-10=0\\ \\ x^2+4x-6=0\\ \\ \\ coeficientes\\ \\ a=1\\ b=4\\ c=-6\\ \\ \\ \Delta=b^2-4ac\\ \Delta=4^2-4(1)(-6)\\ \Delta=16+24\\ \Delta=40$

$x=\dfrac{-b\pm\sqrt{\Delta} }{2a}\\ \\ \\ x=\dfrac{-4\pm\sqrt{40} }{2(1)}=\dfrac{-4\pm(\sqrt{4} .\sqrt{10}) }{2}=\dfrac{-4\pm2\sqrt{10} }{2}=\dfrac{\not2(-2\pm\sqrt{10} }{\not2}=-2\pm\sqrt{10} \\ \\ \\\boxed{ x'=-2+\sqrt{10} }\\ \\\boxed{ x"=-2-\sqrt{10} }$