• Matéria: Matemática
  • Autor: joabsonsilva600000
  • Perguntado 3 anos atrás

Dada a função f(x) = 3x – 2 , determine f(0), f(3), f(5), f(-2) e f(-1).

Respostas

respondido por: rafames1000
1

Resposta:

f(0) = –2

f(3) = 7

f(5) = 13

f(–2) = –8

f(–1) = –5

Explicação passo a passo:

f(x) = 3x – 2

f(0) = 3(0) – 2

f(0) = 0 – 2

f(0) = –2

f(3) = 3(3) – 2

f(3) = 9 – 2

f(3) = 7

f(5) = 3(5) – 2

f(5) = 15 – 2

f(5) = 13

f(–2) = 3(–2) – 2

f(–2) = –6 – 2

f(–2) = –8

f(–1) = 3(–1) – 2

f(–1) = –3 – 2

f(–1) = –5

respondido por: jmarcosrcastro
0

Resposta:

f(0)

f(x) = 3x - 2

f(0)=3.0 - 2

f(0)= -2

f(3)

f(x) = 3x -2

f(3) = 3.3 -2

f(3)= 9-2

f(3) = 7

f(5)

f(x) = 3x -2

f(5)= 3.5 -2

f(5) = 15 - 2

f(5) = 13

f(-2)

f(x) = 3x -2

f(-2)= 3. (-2) -2

f(-2) = -6 -2

f(-2)= -8

f(-1)

f(x) = 3x -2

f(-1)=3.(-1) -2

f(-1) = -3-2

f(-1)= -5

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