Question

Calcule o perímetro do triângulo ABC, sabendo que A(1,3), B(7,3) e C(7,11).

Answer 1

A (1,3) , B (7,3) e C (7,11)

d= √(X₂-X₁)²+(Y₂-Y₁)² 
dAB= √(7-1)² + (3-3)²
dAB= √(6)²+(0)²
dAB= √36+0
dAB= $\sqrt{36}$
dAB= 6u

dAC= √(7-1)² + (11-3)²
dAC= √(6)² + (8)²
dAC= √36+64
dAC= $\sqrt{100}$
dAC= 10u

dBC= √(7-7)² + (11-3)²
dBC= √(0)²+(8)²
dBC= √ 0+64
dBC= $\sqrt{64}$
dBC= 8u

Perímetro do triângulo: 6u+10u+8u= 24u