Question

sendo log2=0,30 e log3=0,48,resolver a equação exponencial 6*=8

Answer 1

6*x =8      log 6*x =log 8    x= log8/log 6=3 log 2/log 2 +log 3 =                       

3 .0,30/0,30+0,48=0,90/0,78≈1,15