Utilizando as regras de derivação, faça o cálculo ANEXO
Anexos:
Lukyo:
Letra B. Em breve posto a resposta.
Respostas
respondido por:
2
Boa noite Carossi!
Solução!
![\dfrac{\partial x^{2} cos(x)}{\partial x } \\\\\\
Regra ~~de~~ diferenciaca\~ao\\\\\\\
\dfrac{\partial x^{2}cos(x) }{\partial x}+ \dfrac{\partial cos(x) x^{2} }{\partial x}\\\\\\\
Simplificada!\\\\\\\
cos(x) \dfrac{\partial x^{2} }{\partial x}+ \dfrac{\partial cos(x)}{\partial x} x^{2} \\\\\\\\
cos(x).2x+ \dfrac{\partial cos(x)}{\partial x}. x^{2} \\\\\\\\\
2cos(x).x+ \dfrac{\partial cos(x)}{\partial x}. x^{2} \\\\\\\\\](https://tex.z-dn.net/?f=+%5Cdfrac%7B%5Cpartial+x%5E%7B2%7D+cos%28x%29%7D%7B%5Cpartial+x+%7D+%5C%5C%5C%5C%5C%5C%0ARegra+%7E%7Ede%7E%7E+diferenciaca%5C%7Eao%5C%5C%5C%5C%5C%5C%5C%0A+%5Cdfrac%7B%5Cpartial+x%5E%7B2%7Dcos%28x%29+%7D%7B%5Cpartial+x%7D%2B+%5Cdfrac%7B%5Cpartial+cos%28x%29+x%5E%7B2%7D+%7D%7B%5Cpartial+x%7D%5C%5C%5C%5C%5C%5C%5C%0ASimplificada%21%5C%5C%5C%5C%5C%5C%5C%0Acos%28x%29+%5Cdfrac%7B%5Cpartial++x%5E%7B2%7D+%7D%7B%5Cpartial+x%7D%2B+%5Cdfrac%7B%5Cpartial+cos%28x%29%7D%7B%5Cpartial+x%7D++x%5E%7B2%7D+%5C%5C%5C%5C%5C%5C%5C%5C%0Acos%28x%29.2x%2B+%5Cdfrac%7B%5Cpartial+cos%28x%29%7D%7B%5Cpartial+x%7D.+x%5E%7B2%7D+%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A2cos%28x%29.x%2B+++%5Cdfrac%7B%5Cpartial+cos%28x%29%7D%7B%5Cpartial+x%7D.+x%5E%7B2%7D+%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%0A%0A+++ "\dfrac{\partial x^{2} cos(x)}{\partial x } \\\\\\
Regra ~~de~~ diferenciaca\~ao\\\\\\\
\dfrac{\partial x^{2}cos(x) }{\partial x}+ \dfrac{\partial cos(x) x^{2} }{\partial x}\\\\\\\
Simplificada!\\\\\\\
cos(x) \dfrac{\partial x^{2} }{\partial x}+ \dfrac{\partial cos(x)}{\partial x} x^{2} \\\\\\\\
cos(x).2x+ \dfrac{\partial cos(x)}{\partial x}. x^{2} \\\\\\\\\
2cos(x).x+ \dfrac{\partial cos(x)}{\partial x}. x^{2} \\\\\\\\\")
![Aplicando ~~a~~ regra ~~de~~ diferenciac\~ao ~~novamente!\\\\\\\
2cos(x)-sen(x). x^{2}\\\\\\
2cos(x)- x^{2} sen(x)\\\\\\
\dfrac{\partial f}{\partial x}= 2cos(x)- x^{2} sen(x)\\\\\\\\\\\\
\boxed{Resposta:2cos(x)- x^{2} sen(x)}\\\\\\\
\boxed{Resposta:D}](https://tex.z-dn.net/?f=Aplicando+%7E%7Ea%7E%7E+regra+%7E%7Ede%7E%7E+diferenciac%5C%7Eao+%7E%7Enovamente%21%5C%5C%5C%5C%5C%5C%5C%0A2cos%28x%29-sen%28x%29.+x%5E%7B2%7D%5C%5C%5C%5C%5C%5C%0A2cos%28x%29-+x%5E%7B2%7D+sen%28x%29%5C%5C%5C%5C%5C%5C%0A+%5Cdfrac%7B%5Cpartial+f%7D%7B%5Cpartial+x%7D%3D+2cos%28x%29-+x%5E%7B2%7D+sen%28x%29%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3A2cos%28x%29-+x%5E%7B2%7D+sen%28x%29%7D%5C%5C%5C%5C%5C%5C%5C%0A+%5Cboxed%7BResposta%3AD%7D%0A%0A%0A%0A+%0A "Aplicando ~~a~~ regra ~~de~~ diferenciac\~ao ~~novamente!\\\\\\\
2cos(x)-sen(x). x^{2}\\\\\\
2cos(x)- x^{2} sen(x)\\\\\\
\dfrac{\partial f}{\partial x}= 2cos(x)- x^{2} sen(x)\\\\\\\\\\\\
\boxed{Resposta:2cos(x)- x^{2} sen(x)}\\\\\\\
\boxed{Resposta:D}")
Boa noite!
Bons estudos!
Solução!
Boa noite!
Bons estudos!
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