Question

calcule a soma dos onze primeiros termos da pg (1/32, 1/16, 1/8)

Answer 1

Olá Stelfy

PG

u1 = 1/32
u2 = 1/16
u3 = 1/8 

razão
q = u2/u1 = (1/16)/(1/32) = 2

soma
Sn = u1*(q^n - 1)/(q - 1)

S11 = (1/32) * (2^11 - 1)/(2 - 1)

S11 = (2048 - 1)/32 = 2047/32 

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