Question

qual e o resultado dessa equaçãox2+4×-12=0

Answer 1

Resolução pela fórmula de Bhaskara, veja:


$x^{2}+4x-12=0\\\\\\ x = -b~\pm~\dfrac{ \sqrt{b^{2}-4~.~a~.~c}}{2~.~a}\\\\\\ x= -4~\pm~\dfrac{ \sqrt{4^{2}-4~.~1~.~(-12)}}{2~.~1}}\\\\\\\ x=-4~\pm~\dfrac{ \sqrt{16+48}}{2}\\\\\\ x = -4~\pm~\dfrac{ \sqrt{64}}{2}\\\\\\ x=-4~\pm\dfrac{8}{2}}\\\\\\\ x'=\dfrac{-4+8}{2}}\\\\\\ x' = \dfrac{4}{2}}~\therefore~\large\boxed{\boxed{\boxed{x'=2.}}}\\\\\\\\ x''=\dfrac{-4-8}{2}}\\\\\\ x''=\dfrac{-12}{2}}~\therefore~\large\boxed{\boxed{\boxed{x''=-6.}}}\\\\\\\\ \large\boxed{\boxed{\boxed{\boxed{x'=2~e~x''=-6.}}}}}$

Espero que te ajude :).