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Boa noite Caludete!
Solução!
![y= x^{2} -4x+6\\\\\
Coeficientes!\\\\\\
a=1\\\\
b=-4\\\\
c=6](https://tex.z-dn.net/?f=y%3D+x%5E%7B2%7D+-4x%2B6%5C%5C%5C%5C%5C%0ACoeficientes%21%5C%5C%5C%5C%5C%5C%0Aa%3D1%5C%5C%5C%5C%0Ab%3D-4%5C%5C%5C%5C%0Ac%3D6 "y= x^{2} -4x+6\\\\\
Coeficientes!\\\\\\
a=1\\\\
b=-4\\\\
c=6")
Para obter as coordenadas do vértice da parábola,vamos usar essa formula.
![V\left ( \dfrac{b}{-2a}, \dfrac{\Delta}{-4a} \right )\\\\\\\\\\\
x_{V}= \dfrac{-4}{-2}=2\\\\\\
y_{V}= \dfrac{b^{2}-4.a.c }{-4a} \\\\\\\
y_{V}= \dfrac{(-4)^{2}-4.1.6 }{-4.1} \\\\\\\
y_{V}= \dfrac{16-24 }{-4} \\\\\\\
y_{V}= \dfrac{-8 }{-4}=2 \\\\\\\
Logo!\\\\\\\
\boxed{Vertice\left ( 2,2 \right )}](https://tex.z-dn.net/?f=V%5Cleft+%28+%5Cdfrac%7Bb%7D%7B-2a%7D%2C+%5Cdfrac%7B%5CDelta%7D%7B-4a%7D+%5Cright+%29%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A+x_%7BV%7D%3D+%5Cdfrac%7B-4%7D%7B-2%7D%3D2%5C%5C%5C%5C%5C%5C%0Ay_%7BV%7D%3D+%5Cdfrac%7Bb%5E%7B2%7D-4.a.c+%7D%7B-4a%7D+%5C%5C%5C%5C%5C%5C%5C%0Ay_%7BV%7D%3D+%5Cdfrac%7B%28-4%29%5E%7B2%7D-4.1.6+%7D%7B-4.1%7D+%5C%5C%5C%5C%5C%5C%5C%0A%0Ay_%7BV%7D%3D+%5Cdfrac%7B16-24+%7D%7B-4%7D+%5C%5C%5C%5C%5C%5C%5C%0Ay_%7BV%7D%3D+%5Cdfrac%7B-8+%7D%7B-4%7D%3D2+%5C%5C%5C%5C%5C%5C%5C%0ALogo%21%5C%5C%5C%5C%5C%5C%5C%0A%0A%5Cboxed%7BVertice%5Cleft+%28+2%2C2+%5Cright+%29%7D%0A%0A+++ "V\left ( \dfrac{b}{-2a}, \dfrac{\Delta}{-4a} \right )\\\\\\\\\\\
x_{V}= \dfrac{-4}{-2}=2\\\\\\
y_{V}= \dfrac{b^{2}-4.a.c }{-4a} \\\\\\\
y_{V}= \dfrac{(-4)^{2}-4.1.6 }{-4.1} \\\\\\\
y_{V}= \dfrac{16-24 }{-4} \\\\\\\
y_{V}= \dfrac{-8 }{-4}=2 \\\\\\\
Logo!\\\\\\\
\boxed{Vertice\left ( 2,2 \right )}")
Boa noite!
Bons estudos!
Solução!
Para obter as coordenadas do vértice da parábola,vamos usar essa formula.
Boa noite!
Bons estudos!
gilson16santana:
sendo-xv=-(6/2a) = A=xv=3 e Yv=3
sendo-xv (b/2a)
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