Question

qual valor de x²+20x+100

Answer 1

x² - 20x + 100 = 0

a = 1
b = -20
c = 100

Delta:
Δ = b² - 4ac
Δ = (-20)² - 4 * 1 * 100
Δ = 400 - 400
Δ = 0

Bhaskara:
x = - b ± √Δ / 2a
x = - (-20) ± √0 / 2 * 1
x = 20 ± 0 / 2
x' = 20 - 0 / 2 = 20 / 2 = 10
x'' = 20 + 0 / 2 = 20 / 2 = 10

S = {10}

Espero ter ajudado. Valeu!