Question

x(x-2)=2(x+6) fórmula de bhaskara, pelo AMOOOR de deus, me ajudem

Answer 1

$x(x-2)=2(x+6)\\ x^2-2x=2x+12\\ x^2-4x-12=0\\ \\ \Delta=b^2-4.a.c\\ \Delta=(-4)^2-4.1.(-12)\\ \Delta=16+48\\ \Delta=64\\ \\ x=\frac{-b\pm\sqrt{\Delta}}{2a}\\ \\ x=\frac{4\pm\sqrt{64}}{2.1}=\frac{4\pm8}{2}\\ \\ x_1=\frac{4-8}{2}=\frac{-4}{2}=-2\\ \\ x_2=\frac{4+8}{2}=\frac{12}{2}=6$