Question

escreva a matriz A=(aij)3×4 na qual aij =3i+2j

Answer 1

Oi Jesiel

aij = 3i + 2i

A(1,1) = 3 + 2 = 5
A(1,2) = 3 + 4 = 7
A(1,3) = 3 + 6 = 9
A(1,4) = 3 + 8 = 11

A(2,1) = 6 + 2 = 8
A(2,2) = 6 + 4 = 10
A(2,3) = 6 + 6 = 12
A(2,4) = 6 + 8 = 14

A(3,1) = 9 + 2 = 11
A(3,2) = 9 + 4 = 13
A(3,3) = 9 + 6 = 15
A(3,4) = 9 + 8 = 17 

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