Question

7x2-5x-3=0 matematica bhaskara

Answer 1

7x²-5x-3=0
a=7; b=-5; c=-3
∆=b²-4ac⇒ ∆=(-5)²-4.7.(-3)⇒ ∆=25+84⇒ ∆=109
x=-b±√∆ / 2.a⇒ x=-(-5)± √109 / 2.7⇒ x=5±10,4 / 14
x'=5+10,4/14⇒ x'=15,4/14
x''=5-10,4/14⇒ x''=-5,4/14

$S=( \frac{15,4}{14} ; \frac{-5,4}{14} )$