Question

f (x)= -x2+4x-4
f (x)= x2+4x+4
me ajudem por favor

Answer 1

$f(x)=-x^{2}+4x-4\\ \delta = b^{2}-4ac\\ \delta = 4^{2}-4(-1)(-4)\\ \delta = 16-16 = 0\\ f(x) = \frac{-b+-\sqrt(\delta)}{2a} = \frac{-4}{2(-1)} = 2\\f(x) = 2\\\\ f (x)= x^{2}+4x+4\\\delta = 4^{2}-4(1)(4) = 0\\ f(x) = \frac{-4}{2(1)} = -2\\f(x)= -2$