• Matéria: Matemática
  • Autor: danielexavier03
  • Perguntado 9 anos atrás

1-Sendo sen x=1/2 calcule:
a) cos x
b)tg x
c)sec x
d) cotg x
e) cossec x


Respostas

respondido por: Anônimo
15


sen²x + cos²x=1   se senx=1/2               (1/2)+cos²x=1              1/4+cos²x=1

                                                                                                cos²x=1-1/4

                                                                                   cos²x=3/4

                                                                                   cosx=√3/2

tgx=senx/cosx

tgx=(1/2):√3/2=1/2.2√3=1/√3=√3/3

secx=1/cosx=1:√3/2=2/√3=(2√3)/3

cotgx=   cosx/senx=√3/2:1/2=√3

cossecx=1/senx=1/(1/2)=2


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