Question

x²-4=0     COMO SE RESOLVE?

Answer 1

x²-4=0
Δ=b²-4ac
Δ=0²-4*1*(-4)
Δ=16

x=$\frac{-b+- \sqrt{delta} }{2a}$
x=(-0+-4)/2
x1=4/2=2
x2=-4/2=-2