Question

$x^{2} -7x+6=0$

Answer 1

É só usar Fórmula de Bhaskara:
x²-7x+6=0

Δ=b²-4.a.c
Δ=-7²-4.1.6
Δ=49-24
Δ=25

-b+-√Δ ÷ 2
-(-7)+-√25 ÷ 2
7+-5 ÷ 2

x= 7+5 = 12 ÷ 2 = 6 ⇒ x=6
x''= 7-5 = 2 ÷ 2 = 1 ⇒ x''=1

Resposta:
(6,1) / (1,6)

Answer 2

Vamos lá:

$x^2-7x+6=0 \\ \\a=1 \\ b=-7 \\ c=6 \\ \\ \Delta=b^2-4ac \\ \Delta =7^2-4*1*6 \\ \Delta =49-24 \\ \Delta =25 \\ \\ x= \frac{-b\pm \sqrt{\Delta }}{2a} \\ x= \frac{-(-7)\pm \sqrt{25}}{2} \\ x= \frac{7\pm5}{2} \\ \\x(1)= \frac{7+5}{2}=6 \\ x(2)=\frac{7-5}{2}=1 \\ \\ S=(1,6)$

Espero ter ajudado!