Question

boa  noite.  como  faço  para   calcular?[tex]senoπ3 + senoπ4 -seno2π

Answer 1

$sen \frac{\pi}{3} = \frac{\sqrt3}{2} \\ sen \frac{\pi}{4}=\frac{\sqrt2}{2} \\ sen 2\pi=0$

Logo o resultado é 

$\frac{\sqrt3}{2}+\frac{\sqrt2}{2}-0=\frac{\sqrt3+\sqrt2}{2}$