Question

Derivada $f(x)= \frac{1}{a} ( bx^{2} +c)-lnx$

Answer 1

$f(x)= \dfrac{1}{a} \cdot(bx^2+c)-ln(x)\\\\\\f'(x)= \dfrac{2bx}{a} - \dfrac{1}{x} \\\\\\\boxed{f'(x)= \dfrac{2bx^2-a}{ax}}$