Question

A=(aij)3x3 tal que aij = 4i-3j+1

Answer 1

║a₁₁ a₁₂ a₁₃║              Calculando com aij = 4i-3j+1

║a₂₁ a₂₂ a₂₃║              a₁₁ = 4.1-3.1+1 = 4-3+1= 1+1 = 2

║a₃₁ a₃₂ a₃₃║              a₁₂ = 4.1-3.2+1 = 4-6+1= -2+1 = -1

                                   a₁₃ = 4.1-3.3+1 = 4-9+1= -5+1 = -4

                                   a₂₁ = 4.2-3.1+1 = 8-3+1= 5+1 = 6

                                   a₂₂ = 4.2-3.2+1 = 8 - 6+1= 2+1 = 3

                                   a₂₃ = 4.2-3.3+1 = 8 - 9+1= -1+1 = 0

                                   a₃₁ = 4.3-3.1+1 = 12 - 3+1= 9+1 = 10

                                   a₃₂ = 4.3-3.2+1 = 12 - 6+1= 6+1 = 6

                                   a₃₃ = 4.3-3.3+1 = 12 - 9+1= 3+1 = 4

A matriz é = ║ 2   -1   -4 ║

                    ║ 6     3     0║

                    ║10    6     4║