Question

qual a equação 16ײ+40×+25=0

Answer 1

16x² + 40x + 25 = 0
a)16  b) 40  c) 25
Δ = b² - 4ac
Δ = 40² - 4 * 16 * 25
Δ = 1600 - 1600
Δ = 0

x = (-b + √Δ) / 2a
x= -40 / 2 * 16
x= -40 / 32
x = - 5/4

Answer 2

$\frac{-40± \sqrt{ 40^{2}-4.16.25 } }{2.16}$
-40±$\frac{\sqrt{1600-1600} }{32}$
$\frac{-40+0}{32} = \frac{-40}{32}= \frac{-5}{4}$
$\frac{-40-0}{32} = \frac{-40}{32} = \frac{-5}{4}$
$\left \{ {{y= \frac{-5}{4} } \atop {x= \frac{-5}{4} }} \right.$