• Matéria: Matemática
  • Autor: genuvan
  • Perguntado 8 anos atrás

qual o mdc de 9,21,36?

Respostas

respondido por: geovanirodrigue
0
mdc(24,36) = 12 
24/2 36/2 
12/2 18/2 
6/2 9/3 
3/3 3/3 
1 1 

2² x 3¹ = 12 

mdc(20,32) = 4 
32/2 20/2 
16/2 10/2 
8/2 5/5 
4/2 1 
2/2 


2² = 4 

mdc(54,81) = 27 
81/3 54/2 
27/3 27/3 
9/3 9/3 
3/3 3/3 
1 1 

3³ = 27 

mdc(60,90) = 60 
90/2 60/2 
45/3 30/2 
15/3 15/3 
5/5 5/5 
1 1 

2¹ x 3¹ x 5¹ = 60 

mdc(18,24) = 6 
24/2 18/2 
12/2 9/3 
6/2 3/3 
3/3 1 

2¹ x 3¹ = 6 


mdc(15,14) = 1 

mdc(14,42) = 14 
42/2 14/2 
21/3 7/7 
7/7 1 

2¹ x 7¹ = 14 

mdc(150,30) = 30 

mmc(18,30,45) = 90 
18,30,45/2 
9,15,45/3 
3,5,15/3 
1,5,5/5 

2¹ x 3² x 5¹ = 90 

mmc(60,90,120) = 360 
60,90,120/2 
30,45,60/2 
15,45,30/2 
15,45,15/3 
5,15,5/3 
5,5,5/5 

2³ x 3² x 5¹ = 360 

mmc(21,28,35) = 420 
21,28,35/2 
21,14,35/2 
21,7,35/3 
7,7,35/5 
7,7,7/7 

2² x 3¹ x 5¹ x 7¹ = 420 

mmc(22,33,44) = 132 
22,33,44/2 
11,33,22/2 
11,33,11/3 
11,11,11/11 

2² x 3¹ x 11¹ = 132
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