Question

Considerando log 2 = 0,3010 e log 3 = 0,4771, calcule

A] Log 8

B] Log 12

C] Log 72

D] Log√2

E] Log √108

F] Log 5

Answer 1

a) log8=log2^3
2log3=2.0,3010=0,6020

b)log12=log2.2.3=log2+log2+log3
                       0,3010+0,3010+0,4771=1,0791

c) log72=log2^3.3^2
log2^3+log3^2=3log2+2log3

3.0,3010+2.0,4771
0,903+0.9542
1,8572

d)log√2

log2^1/2

1/2log2
0,3010/2=0,1505

e) log√108

log2^2.3^3
log2^2+log3^3

2.log2+3log3
2.0,3010+3.0,4771
0,602+1,4313=2,0333

e)log5

log10/2

log10-log2

1-0,3010=0,699