Question

como resolvo essa equação de trigonometria:

 

y=sen 0+π/2-sen 3π/2

________________________      

            2sen π/6

 

quero uma resposta.... 

Answer 1

y = [sen(0+π/2)-sen(3π/2)] / [2sen(π/6)]

 

y = [1-(-1)] / [2*1/2]

 

y = [2] / [1]

 

y = 1

Answer 2

Olá, Kathlyn.

 

$<var>\pi \text{ radianos}=180\º</var>$

 

$<var>sen\ 0=0 \\\\ sen\ \frac{3\pi}{2}=sen\ \frac{3\cdot180\º}{2}=sen\ 270\º=-1\\\\sen\ \frac{\pi}6=sen\ \frac{180\º}{6}=sen\ 30\º=\frac12</var>$

 

Portanto:

 

$y=\frac{\overbrace{sen0}^{=0}+\frac{\pi}{2}-\overbrace{sen\frac{3\pi}{2}}^{=-1}}{2\underbrace{sen\frac{\pi}{6}}_{=\frac12}}}$

 

$<var>y=\frac{0+\frac{\pi}{2}-(-1)}{2\cdot \frac{1}{2}}=\frac{\pi}{2}+1</var>$