Question

x2+2x-8=0?? conta com a resposta

Answer 1

x2+2x-8=0
Δ=b2-4ac
Δ=2²-4×(-8)
Δ=4+32
Δ=36
x=$\frac{-b+- \sqrt{Δ} }{2}$
x=$\frac{-2+-\sqrt{36} }{2}$
x=$\frac{-2+-6}{2}$
x¹=2
x²=-4