Question

log(√2) (3x^2+7x+3)=0 ??

Answer 1

1/2 (3x^2 + 7x + 3) = 0
1/2^0 = 3x^2 + 7x + 3
1 = 3x^2 + 7x + 3
3x^2 + 7x + 3 - 1
3x^2 + 7x + 2 = 0
delta = b^2-4.a. c
delta=49.24=25

x= -b+- √delta/2a
delta= -7+- 5/6
12/6= 2
-12/6= -2

S={-2,2}