• Matéria: Matemática
  • Autor: mariafer3
  • Perguntado 9 anos atrás

torne irredutíveis as frações (15/24) (16/6) (28/49) (35/45) (36/27) (105/63) (68/64)

Respostas

respondido por: DanielS6
5
15/24 (: 3) = 5/8

16/6 (: 2) = 8/3

28/49 (: 7) = 4/7

35/45 (: 5) = 7/9

36/27 (: 9) = 4/3

105/63 (: 21) = 5/3

68/64 (: 4) = 17/16
respondido por: IgorLM
1
(15/24) = 5/8
(16/6)  = 8/3
(28/49) = 4/7
(35/45) = 7/9
(36/27) = 4/3
(105/63) = 35/21 = 5/3
(68/64) = 34/32 = 17/16
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