Question

Seja a função definida por y=x²-2x+1

Answer 1

=> Y=x²-2x+1 <=
y= (-1)²-2(-1)+1 = 4
y= 0²-2*0+1 = 1
y= 1²-2*1+1 = 0
y= 2²-2*2+1 = 1
y= 3²-2*3+1 = 4

x= [-1; 0; 1; 2; 3]
y= [4; 1; 0; 1; 4]
(x,y) = {(-1;4); (0,1); (1;0) ; (2;1); (3;4)}

Answer 2

Resposta:

=> Y=x²-2x+1 <=

y= (-1)²-2(-1)+1 = 4

y= 0²-2*0+1 = 1

y= 1²-2*1+1 = 0

y= 2²-2*2+1 = 1

y= 3²-2*3+1 = 4

x= [-1; 0; 1; 2; 3]

y= [4; 1; 0; 1; 4]

(x,y) = {(-1;4); (0,1); (1;0) ; (2;1); (3;4)}