Question

o numero de raizes reais de:
3^(2x²-7x+5 )=1

Answer 1

3^(2x²-7x+5 )=1 

3^(2x²-7x+5 ) = 3^0

2x²-7x+5  = 0

a = 2 , b = -7 , c = 5 

▲ = b² - 4ac = (-7)² - 4(2)(5) = 49 -40 = 9

▲ = 9

x = -b ± √▲ /2a 

x1 = 7 + 3/ 4 = 10/4 = 5/2

x2 = 7 - 3 /4 = 4/4 = 1

S ={ 1, 5/2}