Question

Interpole 5 meios geométricos que entre 15 e 105

Answer 1

a1=15 a7=105 
an=a1*q^n-1
105=15*q^6
q^6=105/15
q^6=7
q=6√7 (raiz sexta de sete)
q=7^(1/6)
(15; 20,7; 28,56; 39,42; 54,40; 75,07; 105)