Respostas
respondido por:
2
A(1, -4)
B(5, 2)
C(4, k/2)
![\left[\begin{array}{ccc}1&-4&1\\5&2&1\\4&k/2&1\end{array}\right] \neq 0 \\ \\ (1.2.1 + 4.-4.1 + 1.5.k/2) - [(4.2.1) + (1.1.k/2) +(5.-4.1)] \\ \\ (2 - 16 +5/2k) - [(8 + k/2 - 20)] \\ \\ (-14 + 5/2k) - (-12 + k/2) \\ \\ -14 + 5/2k + 12 - k/2 \neq 0 \\ \\ -2 + 5/2k - k/2 \neq 0 \\ \\ 4/2k \neq 2 \\ \\ 2k \neq 2 \\ \\ k \neq 1 \\ \\](https://tex.z-dn.net/?f=++%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26amp%3B-4%26amp%3B1%5C%5C5%26amp%3B2%26amp%3B1%5C%5C4%26amp%3Bk%2F2%26amp%3B1%5Cend%7Barray%7D%5Cright%5D++%5Cneq+0+%5C%5C++%5C%5C+%281.2.1+%2B+4.-4.1+%2B+1.5.k%2F2%29+-+%5B%284.2.1%29+%2B+%281.1.k%2F2%29+%2B%285.-4.1%29%5D+%5C%5C++%5C%5C+%282+-+16++%2B5%2F2k%29+-+%5B%288+%2B+k%2F2+-+20%29%5D+%5C%5C++%5C%5C+%28-14+%2B+5%2F2k%29+-+%28-12+%2B+k%2F2%29+%5C%5C++%5C%5C+-14+%2B+5%2F2k+%2B+12+-+k%2F2++%5Cneq+0+%5C%5C++%5C%5C+-2+%2B+5%2F2k+-+k%2F2++%5Cneq++0+%5C%5C++%5C%5C+4%2F2k++%5Cneq+2+%5C%5C++%5C%5C+2k++%5Cneq+2+%5C%5C++%5C%5C+k++%5Cneq+1+%5C%5C++%5C%5C+ "\left[\begin{array}{ccc}1&-4&1\\5&2&1\\4&k/2&1\end{array}\right] \neq 0 \\ \\ (1.2.1 + 4.-4.1 + 1.5.k/2) - [(4.2.1) + (1.1.k/2) +(5.-4.1)] \\ \\ (2 - 16 +5/2k) - [(8 + k/2 - 20)] \\ \\ (-14 + 5/2k) - (-12 + k/2) \\ \\ -14 + 5/2k + 12 - k/2 \neq 0 \\ \\ -2 + 5/2k - k/2 \neq 0 \\ \\ 4/2k \neq 2 \\ \\ 2k \neq 2 \\ \\ k \neq 1 \\ \\")
Espero ter ajudado.
B(5, 2)
C(4, k/2)
Espero ter ajudado.
Help89:
muito Obrigado mas nao consguir entender :D
Tem que resolver por matriz. calcular o determinante que deverá ser diferente de 0.
nao consigo entender :/ mas Obrigado mesmo Assim :D
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