Question

seja f:N -N a funçao dada por f(x) x²+1/x qual valor de f(3)+f(1/3)

Answer 1

f(3)=3²+1/3=9+1/3=28/3
f(1/3)=(1/3)²+1/(1/3)=1/9+(1*3/1)=1/9+3=28/9
f(3)+f(1/3)=28/3+28/9=(84+28)/9=112/9