Question

determine o valor numérico de cada expressão

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Answer 1

a)  $\frac{ \frac{1}{2} }{ \frac{1}{2} + \frac{1}{3} } = \frac{ \frac{1}{2} }{ \frac{3+2}{6} } = \frac{1}{2} * \frac{6}{5} = \frac{3}{5}$

b)  $9+ \frac{1}{9} - \sqrt{9} = 9+ \frac{1}{9} -3= \frac{81+1-27}{9} = \frac{55}{9} =6 \frac{1}{9}$

c)  $\frac{ \frac{ 1^{2} }{3}- (-1)^{2} }{ \frac{ 1^{2} }{3}+(-1)^{2} } = \frac{ \frac{1}{3}-1 }{ \frac{1}{3}+1 } = \frac{ \frac{1-3}{3} }{ \frac{1+3}{3} } = \frac{- \frac{2}{3} }{ \frac{4}{3} } =- \frac{2}{3} * \frac{3}{4} = - \frac{1}{2}$

d)  $\frac{2* \frac{1}{2}*2-3* \frac{1}{2} }{ \frac{1}{2}+2} = \frac{2- \frac{3}{2} }{ \frac{1}{2} +2} = \frac{ \frac{4-3}{2} }{ \frac{1+4}{2} } = \frac{1}{2} * \frac{2}{5} = \frac{1}{5}$

e)  $\frac{2+ \frac{1}{2}+ 2^{2} }{2-1} = \frac{2+ \frac{1}{2} +4}{1} = \frac{4+1+8}{2} = \frac{13}{2} =6 \frac{1}{2}$

f)  $\frac{ 2^{2} +2*2*(-3)+ (-3)^{2} }{2+(-3)} = \frac{4-12+9}{-1} = \frac{13-12}{-1} = \frac{+1}{-1} =-1$

g)  $\frac{1}{3} +3= \frac{1+9}{3} = \frac{10}{3} =3 \frac{1}{3}$