Question

10y-5(1+y)=3(2y-2)-20

Answer 1

10y-5(1+y)=3(2y-2)-20
10y - 5 - 5y = 6y - 6 - 20
10y - 5y - 6y = - 6 - 20 + 5
- y = - 21 . ( - 1)
y = 21

Answer 2

10y-5(1+y)=3(2y-2)-20

10y-5-5y=6y-6-20

10y-5y-6y=-6-20+5

-y=-21
y=21
S={21}