Question

sendo x = (2²)³, y = 2³, y = z = 2³², o valor de xyz é:

Answer 1

12 =34 $55678888533221

Answer 2

$x.y.z \\\\( 2^{2} )^{3} . 2^{3} . 2^{32} \\\\ 2^{2.3} . 2^{3} . 2^{32} \\\\ 2^{6} . 2^{3+32} \\\\ 2^{6} + 2^{35} \\\\ 2^{6+35} =\boxed{\boxed{ 2^{41} }}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ok$