Question

determine a matriz B= (bij)3x2,sendo bij = 2+i+j.

Answer 1

$B= \left[\begin{array}{ccc}b11&b12\\b21&b22\\b31&b32\end{array}\right] \\ \\ \\ \boxed{bij= 2+i+j} \\ \\ b11=2+1+1= 4 \\ b12=2+1+2= 5 \\ b21= 2+2+1=8 \\ b22=2+2+2= 6 \\ b31= 2+3+1= 6 \\ b32=2+3+2= 7$

Agora podemos montar a matriz.

$B= \left[\begin{array}{ccc}4&5\\8&6\\6&7\end{array}\right]$