Question

2+3[x-(3x+1)]=5[x-(2x-1)]

Answer 1

2 + 3[x - (3x+1)] = 5 [ x -(2x-1)]
2 + 3 [ x - 3x - 1] = 5 [ x -2x + 1]
2 + 3 [ -2x -1 ] = 5 [ -x + 1 ]
2 - 6x - 3  = -5x + 5 
-6x - 3 + 2 = -5x + 5
-6x - 1 = -5x + 5 
-6x + 5x = 5 + 1
-x = 6   (-1)
x = -6

Resposta : x = -6