Question

qual solucao x²-8x-=0

Answer 1

x² - 8x +0=0
Δ=b²-4 ac
Δ= (-8)² - 4.1.0
Δ=64

x=-b +/- √Δ/ 2a
x= -(-8) +/- √64 / 2.1
x'= $\frac{8+8}{2}$
x'=$\frac{16}{2}$
x'=8

x''= $\frac{8-8}{2}$
x''=$\frac{0}{2}$
x''= 0

Answer 2

x² - 8x = 0
x.(x - 8) = 0
x = 0
(x - 8) = 0
x - 8 = 0
x = + 8

S[0 ; 8]