Question

como descobrir a raiz de x² -10x = 0

Answer 1

x^2 - 10x=0
x(x-10)=0
x=0 v x=10

Answer 2

Resolvendo por Bháskara.

$x 2 - 10x = 0 \\ \\ \\ x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=1, b=−10, c=0

Δ=b2−4ac
Δ=(−10)2−4*(1)*(0)
Δ=100+0
Δ=100

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a} \\ \\ x = \dfrac{-(-10) \pm \sqrt{100}}{2*1} \\ \\ x = \dfrac{10 \pm 10}{2} \\ \\ x' = \dfrac{10 + 10}{2} \\ \\ x' = \dfrac{20}{2} \\ \\ x' = 10 \\ \\ \\ x'' = \dfrac{10 - 10}{2} \\ \\ x'' = \dfrac{0}{2} \\ \\ x'' = 0$

S ={10, 0}