Question

(2m+n/4)² Quanto dá? Me explica, por favor

Answer 1

$(2m+ \frac{n}{4})^{2} = 4m^{2}+ \frac{4mn}{4} + \frac{n^{2} }{16} => 4m^{2}+mn+ \frac{n^{2}}{4} :.$ ou $(2m+ \frac{n}{4})*(2m+ \frac{n}{4}) = 4m^{2}+ \frac{2mn}{4}+ \frac{2mn}{4} + \frac{n^{2} }{16} => 4m^{2}+ \frac{4mn}{4}+ \frac{n^{2}}{4}\\4m^{2}+ mn+ \frac{n^{2}}{4} :.$