Question

(1/3) elevado a 3 - (-1/3) elevado a 3 + (3/2) elevado a -2

Answer 1

Olá.

$\mathsf{\left(\dfrac{1}{3}\right)^{3}-\left(-\dfrac{1}{3}\right)^{3}+\left(\dfrac{3}{2}\right)^{-2}=\dfrac{1^3}{3^3}+\dfrac{1^3}{3^3}+\dfrac{2^2}{3^2}=}\\\\\mathsf{\dfrac{1}{27}+\dfrac{1}{27}+\dfrac{4}{9}=\dfrac{1+1+3\cdot4}{27}=\dfrac{1+1+12}{27}=\boxed{\mathsf{\dfrac{14}{27}}}}$

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Bons estudos.