Question

Transforme as dizima periódicas em fração geratriz a)0,999 b)2,111 c)0,121212 d)3,323232 e)0,243243243 f)8,343343

Answer 1

a)0,999 = 9/9
b)2,111 = 2 + 1/9 = 2x9+1/9 =18+1/6 = 19/9 
c)0,121212 = 12/99 = simplifica = 4/33
d)3,323232 = 3 + 32/99 = 3 x 99 + 32/99 = 297 + 32/99 = 329/99 
e)0,243,243,243,, = 243/999 = 81/333  = 27/111 = 9/37
f)8,343 343 = 8 + 343/999 = 8 X 999 + 343/999 = 7992 + 343/999 = 8335/999