Question

5/6 - 1/3 ?como faço 0,5 +1/2 e 5/6 + 1,3 + 1/6 + 0,7

Answer 1

$\text{a) }\frac{5}{6}-\frac{1}{3}=\frac{5}{6}-\frac{1\cdot 2}{3\cdot 2}=\frac{5}{6}-\frac{2}{6}=\frac{5-2}{6}=\frac{3}{6}=\boxed{\bold{\frac{1}{2}}}\\\\\text{b) }0,5+\frac{1}{2}=\frac{1}{2}+\frac{1}{2}=\frac{1+1}{2}=\frac{2}{2}=\boxed{\bold{1}}\\\\\text{c) }\frac{5}{6}+1,3+\frac{1}{6}+0,7\\\\\dfrac{5}{6}+\dfrac{13}{10}+\dfrac{1}{6}+\dfrac{7}{10}\\\\\dfrac{5\cdot 10}{6\cdot 10}+\dfrac{13\cdot 6}{10\cdot 6}+\dfrac{1\cdot 10}{6\cdot 10}+\dfrac{7\cdot 6}{10\cdot 6}$
$\dfrac{50}{60}+\dfrac{78}{60}+\dfrac{10}{60}+\dfrac{42}{60}\\\\\dfrac{50+78+10+42}{60}\\\\\dfrac{180}{60}\\\\\boxed{\bold{3}}$