Question

Inserir 4 termos (meios aritméticos) entre 3 e 38
Me ajudem

Answer 1

Encontrar a razão da PA

an = a1 + ( n -1) . r
38 = 3 + ( 6 -1) . r
38 = 3 + 5r
35 = 5r  
r = 35 / 5
r = 7

=== 
an = a1 + ( n -1) . r = an
an = 3 + ( 1 -1) .7 = 3
an = 3 + ( 2 -1) .7 = 10
an = 3 + ( 3 -1) .7 = 17
an = 3 + ( 4 -1) .7 = 24
an = 3 + ( 5 -1) .7 = 31
an = 3 + ( 6 -1) .7 = 38



PA = (3, 10, 17, 24, 31, 38)