Question

RESOLVA AS EQUAÇOES ABAIXO:

2^X-1=1/64

125^3X=1/5

100^-X=0,001

0,25^X+4=8

5$x^{2} +5 X+6=1$

Answer 1

Vou resolver a primeira, se vc nao entender comente. Se entender resolva as outras:

$2^{x-1}=\dfrac{1}{64}\\\\2^{x-1}=\dfrac{1}{2^6}\\\\2^{x-1}=2^{-6}\\\\x-1=-6\\\\x=-5$