Question

(2/3p³-1/2).(2/3p³+1/2) ME AJUDEM A SIMPLIFICAR PF

Answer 1

$\boxed{(a+b)\cdot (a-b)=a^2-b^2}$

$( \frac{2}{3p^3}- \frac{1}{2} )\cdot ( \frac{2}{3p^3}+\frac{1}{2} )=$

$( \frac{2}{3p^3})^2-( \frac{1}{2} )^2=$

$\frac{2^2}{3^2(p^3)^2}-\frac{1^2}{2^2}=$

$\frac{4}{9p^6}-\frac{1}{4}=$

$\frac{16-9p^6}{36p^6}$