Question

x²+2x+5/9=0 quanto é????

Answer 1

$x^{2} + 2x + \frac{5}{9} = 0$

Δ= b² - 4.a.c
Δ= $2^{2} - 4.1.\frac{5}{9}$
Δ= $4 - \frac{20}{9}$
Δ= $36 - 20$
Δ= $16$

$x = \frac{ 2 +- \sqrt{16} }{2}$

$x_{1} = \frac{2 + 4 }{2}$

$x_{1} = \frac{6}{2}$

$x_{1} = 3$

$x_{2} = \frac{2-4}{2}$

$x_{2} = \frac{-2}{2}$

$x_{2} = -1$

Respostas:

$S = (-1,3)$

ESPERO TER AJUDADO!