Question

Se puderem, por favor, me responder as letras (e) e (g)!!

Answer 1

Use mudança de base: $\boxed{log_ba=\frac{log_na}{log_nb}}$

$log_25=\frac{log5}{log2}=\frac{log(\frac{10}{2})}{log2}=\frac{log10-log2}{log2}=\frac{1-0,301}{0,301}=2,32$

$log_928=\frac{log28}{log9}=\frac{log(4*7)}{log3^2}=\frac{2log2+log7}{2log3}=\frac{2*(0,301)+(0,845)}{2*(0,477)}=1,52$