Question

Dados log 2 = 0,301 ; log 3 = 0,477 ; log 5 = 0,699 e log 7 = 0,8450. Calcule log 0,6

Answer 1

$log(0.6) = log( \frac{6}{10} ) = log( \frac{2 \times 3}{10} ) \\ log(2) + log(3) - log(10) \\ 0.301 + 0.477 - 1 \\ log(0.6) = - 0.292 \\ faustop$